ERROR ANALYSIS
Measurement Errors are not mistakes, but more like a limit of accuracy. There are several common sources for errors - the most obvious is the resolution of the measuring instrument (e.g. to the nearest mm).
Errors in measurements have a carry-through effect in calculations, and this can be analysed to determine the overall error in the final solution.
Symbols: We will use the following symbols:
S = absolute error of a measurement.
x = the measurement itself (the measurand)
S/x = relative error
Sources of Error
Errors can come from various sources. Resolution error is easy to estimate, but the others are usually quite approximate and may have to be estimated by the person taking the measurement.
Random Errors
Systematic Errors: (Inherent in the measurement).
Systematic Errors do not improve by taking many readings, because the average is not zero. Regular calibration is all about minimising systematic error.
These errors should be added together to give the absolute measurement error;
Absolute error = (Resolution / 2) + (misalignment error) + (systematic error) + (inherent error)
Absolute and Relative Error
Absolute Error is the tolerance of the measurement, or the approximate error of a single measurement. The best estimate is the standard deviation of the measurement, which can only be determined with many measurements taken. Failing this, an estimation can be made using the error sources above.
Relative Error is the ratio of the size of the absolute error to the size of the measurement being made.
Relative Error = Absolute Error / Value.
Significant figures: Every measurement (or number) is given to a certain number of significant figures (e.g. Gravitational acceleration = 9.8 m/s2). Generally, we take the last digit quoted in a measured value is the one that has some uncertainty. e.g 34.532 kg. This assumes we can measure to the nearest gram. We would write it as 34.532 +-0.001 kg.
When working with constants, it is important to minimise error by using adequate number of significant figures. For example, Pi is known with very high accuracy, so we wouldn't round it off to 3.14. Use the calculator value of 3.1415926535...!
Remember: The % error in the final solution of a complex calculation is always worse than the % errors of all the measurements. So it only takes 1 bad measurement error to damage the accuracy of the solution.
Example:
(a) A length is measured as 120mm using a ruler graduated in mm. Absolute error = 1mm / 2 = 0.5mm. This would be written as +/- 0.5mm
Relative error = 0.5 / 120 = 0.004167 (or 0.4167%)
(b) The same ruler measures 12mm.
Absolute error = 1mm / 2 = 0.5mm. This would be written as +/- 0.5mm
Relative error = 0.5 / 12 = 0.04167 (or 4.167%)
Working with Errors (Error propagation)
Error will usually accumulate with each calculation, depending on the equations. Sometimes the error can reduce, like when we measure the thickness of a piece of paper by measuring a stack of 100 pages.
Dummy Method: When adding/subtracting we add absolute error. When multiplying/dividing we add relative error. This is easy to understand but overly conservative because errors are actually statistical. This method of error propagation overestimates the combined error because of the possibility that errors can cancel when more than one measurement is made.
Proper Method: If we look at errors statistically, a better approximation of error is given by;
Type of Operation |
Formula |
Errors |
1. Addition and Subtraction |
x = a + b - c |
|
2. Multiplication and Division |
x = a * b/c |
|
3. Exponentiation |
x = ab |
|
4. Logarithm (Base 10) |
x = log10 a |
|
5. Logarithm (Base e) |
x = ln a |
|
6. Antilog (Base 10) |
x = 10a |
|
7. Antilog (Base e) |
x = ea |
Example:
A rectangle measured as 120mm x 75mm using a ruler graduated in mm.
The steel rule has an error of 1mm / 2 = 0.5mm. This would be written as +/- 0.5mm
(a) Find the error in calculating the perimeter
Perimeter = 120 + 75 + 120 + 75 = 390 mm
Absolute Error = sqrt (0.52 + 0.52+ 0.52+ 0.52) = 1 mm
Answer: 390 +-1mm. Which means the perimeter is probably between 389 and 391 mm.
(b) Find the error in calculating the area.
Area = 120+-0.5 * 75+-0.5
Rel Error = sqrt ( (0.5/120)2 + (0.5/75)2 ) = 0.00786 (or 0.786%)
Absolute error = (120 * 75) * Rel Error = 70.75 mm2
Answer: 9000 +-70.8 mm2. Which means the area is probably between 8929.2 and 9070.8 mm2.
Source: http://www.learneasy.info/MDME/MEMmods/MEM30012A/error_analysis_files/Error_Analysis_Notes.doc
Web site to visit: http://www.learneasy.info
Author of the text: indicated on the source document of the above text
If you are the author of the text above and you not agree to share your knowledge for teaching, research, scholarship (for fair use as indicated in the United States copyrigh low) please send us an e-mail and we will remove your text quickly. Fair use is a limitation and exception to the exclusive right granted by copyright law to the author of a creative work. In United States copyright law, fair use is a doctrine that permits limited use of copyrighted material without acquiring permission from the rights holders. Examples of fair use include commentary, search engines, criticism, news reporting, research, teaching, library archiving and scholarship. It provides for the legal, unlicensed citation or incorporation of copyrighted material in another author's work under a four-factor balancing test. (source: http://en.wikipedia.org/wiki/Fair_use)
The information of medicine and health contained in the site are of a general nature and purpose which is purely informative and for this reason may not replace in any case, the council of a doctor or a qualified entity legally to the profession.
The texts are the property of their respective authors and we thank them for giving us the opportunity to share for free to students, teachers and users of the Web their texts will used only for illustrative educational and scientific purposes only.
All the information in our site are given for nonprofit educational purposes